Question

find the are of shaded portion​

Answer 1

## area of the shaded portion=area of trapezium ABCD - area of triangle ##

Trapezium ABCD

i.Height=12 cm

ii.CD = 40 -10 =30cm

iii.AB = 40cm

$area \: of \: trapezium \: = (sum \: of \: parralel \: sides) \: \times height \div 2$

iv.Area = (30+40)×12/2

=70×6

=420cm²

Triangle

i.Height=12cm

ii.Base=10cm

$area \: of \: triangle = 1 \div 2 \: \times base \times height$

iii..Area=1/2×10×12

=10×6

=60cm²

Area of Shaded region=420-60

=360cm²

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