find the are of the given figure ABCDEFG as per dimension given in it
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ABQR,ARPS are squares then AB=BQ=QR=AR=1=AF=FP=AS and AQ,AP are diagonals of length 2 each.
In regular hexagon, each interioi angle =6(6−2)×180=120o
∠FAB=120o
∠RAB=90o=∠FAS as ABQR and AFPS are squares.
∠FAB=∠RAB+∠FAS−∠RAS
∴120o=90o+90o−∠RAS
∠RAS=60o→ △RAS is equvilateral triangle with side =1
SR=1
Similarly PS=1
Also ∠RAS=∠RAQ+∠PAS−∠PAQ
∴60o=45o+45o−∠PAQ
∴∠PAQ=30o
∠ASR=60o and ∠ASP=90o, then
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