Question

Find the are of the iron sheet required to prepare a cone 24 cm high with base radius 7 cm

Answer 1

r = 7cm
h = 24cm
${l} = \sqrt{ {h}^{2} \ + {r}^{2} } \\ {l} = \sqrt{ {24}^{2} \ + {7}^{2} } \\ {l } = \sqrt{576 + 49}$
${l } = \sqrt{625}$
$l = 25cm$
$area = \pi \times r \times l$
$area = (22 \div 7) \times 7 \times 25$
$area = 550 {cm}^{2}$