Question

Find the are of the shaded portion

Answer 1

Answer:

Area of shaded region = Area of square PQRS - (Area of triangle QRU + Area of triangle TSU + Area of triangle QPT ) = 400 − (100 + 50 + 100) = 400 – 250 = 150 sq. cm. So, the area of the shaded portion = 150 sq. cm.

Answer 2

Given:

Length of the rectangle = 18 cm

Breadth of the rectangle = 10 cm

Legs of ∆AEF = 6 cm and 10 cm

Legs of ∆BEC = 8 cm and 10 cm

Formula:

Area of a rectangle = LB

where, L is the Length and B is the Breadth.

Area of a right triangle = AB/2

where, A and B are the legs of the triangle.

Explanation:

Area of the rectangle = LB

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤﾠ= (18)(10)sq.cm

ﾠㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 180 sq.cm

Area of the ∆AEF = AB/2

ﾠㅤㅤㅤㅤㅤㅤㅤㅤ= (6)(10)/2 sq.cm

ﾠㅤㅤㅤㅤㅤㅤㅤㅤ= 60/2 sq.cm

ﾠㅤㅤㅤㅤㅤㅤㅤㅤ= 30 sq.cm

Area of the ∆BEC = AB/2

ﾠﾠㅤㅤㅤㅤㅤㅤㅤﾠ= (8)(10)/2 sq.cm

ﾠﾠㅤㅤㅤㅤㅤﾠㅤㅤ= 80/2 sq.cm

ﾠﾠﾠㅤㅤㅤㅤㅤㅤㅤ= 40 sq.cm

Area of the shaded portion = Area of the rectangle - The sum of the areas of the two triangles

Area of the shaped portion = 180 sq.cm - (30 + 40) sq.cm = 180 sq.cm - 70 sq.cm = 110 sq.cm

Answer:

The area of the shaded portion is 110 sq.cm .