Question

Find the are of the triangle whose sides are in the ratio of 3:4:5 and the perimeter is 120m​

Answer 1

let the sides be 3x, 4x, and 5x cm long

3x + 4x + 5x = 120

12x = 120

x = 10

so 3x = 30

4x = 40

5x = 50

so the sides are 30cm, 40cm, and 50cm

a = 30, b = 40, c = 50

s = ½p = 60

by Heron's formula,

area = √[s(s-a)(s-b)(s-c)]

= √[60(60-30)(60-40)(60-50)]

= √[60*30*20*10]

= √360000

= 600

therefore the area of the triangle is 600cm²

Answer 2

Here is your answer....

Triangle whose sides are in the ratio of 3x:4x:5x

The perimeter is 120

3x+4x+5x =120

12x. =120

X= 120/12

X =10

Triangle sides are given....

3x=3×10

=30

4x=4×10

=40

5x=5×10

=50

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