Question

find the are of trapezium given that it parallel side are 18cm and 28cm and the distance between then is 12 cm​

Answer 1

Answer:

276 cm²

Step-by-step explanation:

A. of trapezium=1/2×sum of parallel sides×height

=1/2×18+28×12

=1/2×46×12=276cm²

Answer 2

Given :-

• First parallel side of the trapezium = a = 18 cm

• Second parallel side of the trapezium = b = 28 cm

• Height of the trapezium = 12 cm

To Find :-

• Area of the trapezium.

Solution :-

Area of the trapezium :-

$:\implies\:\:\sf{Area= \dfrac{1}{2} \times height \times (a+b)}$

$:\implies\:\:\sf{Area = \dfrac{1}{2} \times 12 \times (18+28)}$

$:\implies\:\:\sf{Area = 6 \times (18+28)}$

$:\implies\:\:\sf{Area = 6 \times 46}$

$\sf:\implies \underline{\boxed{\pink{\mathfrak{Area = 276\: cm^2}}}}$

∴ Area of the trapezium = 276 cm²