Math, asked by beenabuchade887, 8 months ago

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find the are of triangle
Bon, 14om and is
ches
o'whose sides are

Answers

Answered by 22jigyasa4d

0

Answer:

Given sides of triangle

a=13,b=14,c=15

Semi-perimeter s=

2

1

(a+b+c)=

2

1

(13+14+15)=21

Area, A =

s(s−a)(s−b)(s−c)

A=

21(21−13)(21−14)(21−15)

A=84 cm

2

Step-by-step explanation:

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