Question

find the area
a] 12 cm, 14 cm, 12 cm
b] 10 cm, 11 cm, 6 cm

Answer 1

Answer:

Given sides are 18cm,10cm and 14cm

Area of triangle =

s(s−a)(s−b)(s−c)

⇒a=18cm,b=10cm and c=14cm

⇒s=

2

a+b+c

=

2

18+10+14

=

2

42

=21cm

Area =

21(21−18)(21−10)(21−14)

=

21×3×11×7

=21

11

sqcm

Hence, the answer is 21

11

sqcm.

Answer 2

Answer:

a] Sides of the triangle is 12 cm , 14 cm and 12 cm

hence it is a isosceles triangle

we can find the area of the triangle by herons formula .

that is : √{(s-a)(s-b)(s-c)}

s = (12+12+14)/2

s= 38/2

s= 19

√{(19-12)(19-12)(19-14)}

√{(7)(7)(5)

7√5

hence , the area of the triangle is 7√5 cm².

or

area of triangle is 15.7 cm².

b] sides of the triangle is 10 cm , 11 cm and 6 cm

we can find the area using herons formula

formula = √{(s-a)(s-b)(s-c)}

s = (10+11+6 )/2

s = 27/2

s = 13.5

√{(13.5-10)(13.5-11)(13.5-6)}

√{(3.5)(2.5)(7.5)

√65.625

8.1

hence ,the area of the triangle is 8.1 cm².

Step-by-step explanation:

Area of first triangle is 15.7 cm² .

Area of second triangle is 8.1 cm².