Question

find the area (A) and the perimeter (P) of the square whose side measures are 9.5cm.

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Answer 1

Answer:

area - s×s = 9.5×9.5= 90.25cm² ,, perimeter = 4× side = 4× 9.5 =38 cm

Answer 2

Answer:

Hence the area of a square is $90.25cm^2$ and perimeter is $38 cm .$

Step-by-step explanation:

According to the data given in the question,

It is given that, the side of a square is $9.5$ cm,

We have to find the area of a square,

Here we have to use the formula of area of a square,

The area is equal to side square, i.e. ${\text } A = a^2$

Where a is the side of the square,

Given: a= $9.5$ cm,

Substitute the value in the formula of area of a square, we get

${\text } A = (9.5)^2$

Squaring a number is to multiply the number by itself we get,

${\text } A = 9.5\times 9.5$

Multiply $9.5$ and $9.5$, we get

${\text } A = 90.25cm^2$

Hence the area of a square is $90.25cm^2.$

Now, we have to use the formula of the perimeter of a square.

The perimeter of a square is equal to the length of all $4$ sides of a square.

i.e. ${\text } P = 4 \times a$

${\text } P = 4 \times 9.5$

Multiplying $4$ with $9.5$,

${\text } P = 38 cm$

Hence, the perimeter of a square is $38 cm$.