find the area.......AB is 10cm, BC is 12cm, AC is 10cm
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Answer:
The area of triangle= 48 sq.cm
Step-by-step explanation:
Given side AB = 10cm, BC = 12cm, AC = 10cm
Let a= 10 cm , b= 12cm, c= 10cm
Use Heron's Formula
S = a+ b+ c/2
= 10+12+10/2
=32/2
=16 cm
Area of triangle= √S(S-a)(S-b)(S-c)
=√16(16-10)(16-12)(16-10)
=√16×6×4×6
=√2304
= 48 sq.cm
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