find the area.......AB is 12cm, BC is 13cm, AC is 5cm
Answers
Answered by
0
Answer:
∆=1/2×AB×BC
= 1/2×12×13
=78
Answered by
0
Step-by-step explanation:
In right angles triangle ABC, AB=12cm, BC=13cm and AC=5cm
Area of triangle=
2
1
×base×height=
2
1
×AB×AC
=
2
1
×5×12=30cm
2
Now, in ΔABC,
Area of triangle ABC=
2
1
×BC×AD
⇒30=
2
1
×13×AD
⇒ AD=
13
30×2
=
13
60
cm.
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