Question

Find the area an perimeter of rectangle ABCD​

Answer 1

In ΔBCD, 25²= 7² + DC² ( pythagorous theorem)

so, 625= 49 + DC²

625-49=DC²

So, DC²=576

DC= 24

So,

Perimeter of rectangle ABCD is:

2(l+b)

2(24+7)

2(31)

That is, 62cm

and Area:

lxb

= 24x7=168 cm²

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Answer 2

Step-by-step explanation:

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