Question

find the area and another diagonal of a rhombus each side 20 cm and a diagonal 24 cm .
plz give me step by step solution
class 8th . Mensuration ❣❣​

Answer 1

Answer:

240 is area of rhombus

Explanation:

1/2×(diagonal1×diagonal2)

1/2×(20×24)

1/2×(480)

1/2×480

1×240

240

Answer 2

GIVEN :

• Each side of a rhombus = 20 cm.
• Diagonal of a rhombus = 24 cm.

TO FIND :

• The area of a diagonal = ?

SOLUTION :

To find the area of a diagonal,

Given that,

In the rhombus PQRS,

Let PQ = 20 cm and PR = 24 cm.

From the given diagram,

PO + RO = 24 cm.

PO = 12 cm ........ { PO is equal to the CO }

In triangle POQ,

PQ = 20 cm and PO = 12 cm.

Now, Using the pythagoras theorem,

QO = $\implies \sf \sqrt {20^{2} - 12^{2}} cm$

QO = $\implies \sf \sqrt {400 - 144}$

QO = $\implies \sf \sqrt {256} \ cm$

QO = $\implies \sf 16 \ cm$

Therefore,

QO = SO = 16 cm.

Hence,

QS = 16 + 16 = 32 cm.

$\large \red {\boxed {\sf Area \ of \ rhombus \ = \ \dfrac {1}{2} \times diagonal 1 \times diagonal 2}}$

$\implies \sf \dfrac {1}{2} \times PR \times QS$

$\implies \sf 384 \ cm^{2}$

•°• The area of a rhombus is 384 cm².