Question

Find the area
and circumference of circle
whose radius is 28m​

Answer 1

Let r be the radius of the circle.

Then according to the problem we've r=28m.

Then perimeter will be (P)=2πr

(P) = 2×(22÷7)×28

(P) = 176m

So the perimeter of the circle is 176m.

(A) = π(r)^2

(A) = (22÷7)×(28)^2

(A) = 22÷7)×28×28

(A) = (22÷7)×784

(A) = (22×784)÷7

(A) = 17248÷7

(A) = 2464m

So the area is 2464m.

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Answer 2

$\bf \: Given \: :$ ↴

$\sf \: Radius \: of \: the \: circle \: : \: 28 \: meter.$

$\bf \: To \: find \: :$ ↴

$\sf \: Area \: and \: circumference \: of \: circle.$

$\bf \: So, \: Let's \: Start \: :$ ↴

$\sf \: First \: of \: all \: we \: will \: find \: the \: circumference \: of \: the \: circle.$

$\boxed{{ \purple{ \sf \: Circumference \: of \: the \: circle \: : \: 2πr }}}$

$\sf \: Putting \: the \: value \: :$ ↴

$\bf \longrightarrow \: 2 \: \times \: \dfrac{22}{7} \: \times 28$

$\bf \longrightarrow \: \dfrac{1232}{7}$

$\bf \longrightarrow \: 176 \: m ^{2}$

$\blue{\sf \: So, \: the \: Circumference \: of \: the \: circle : 176 \: m ^{2} }$

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$\sf \: Now, \: we \: will \: find \: the \: area \: of \: the \: circle.$

$\boxed{ \purple{ \sf \: Area \: of \: the \: Circle : πr ^{2} }}$

$\sf \: Putting \: the \: value \: :$ ↴

$\bf \longrightarrow \: \: \dfrac{22}{7} \: \times 28 ^{2}$

$\bf \longrightarrow \: \: \dfrac{22}{7} \: \times 28 \: \times 28$

$\bf \longrightarrow \: \dfrac{17248}{7}$

$\bf \longrightarrow \: 2464 \: m ^{2}$

$\blue{\sf \: So, \: the \: area \: of \: the \: circle : 2464 \: m ^{2} }$