Question

find the area and height of and equilateral triangle whose each side measures 6.4m ( take √3 = 1.73 in each case)
Please tell the correct answer of you and don't answer anything else....... ​

Answer 1

Given :-

• Equilateral triangle whose each side measures 6.4m ( take √3 = 1.73 in each case).

To Find :-

• Area & height of the equilateral triangle.

Solution :-

As we know that,

Height of equilateral Δ = √3/2 × side

[ Putting values ]

↪ Height of equilateral Δ = √3/2 × 6.4

↪ Height of equilateral Δ = √3 × 3.2

↪ Height of equilateral Δ = 1.73 × 3.2

↪ Height of equilateral Δ = 5.536 m.

Now, we know that,

Area of equilateral Δ = √3/4 × side²

[ Putting values ]

↪ Area of equilateral Δ = √3/4 × (6.4)²

↪ Area of equilateral Δ = √3/4 × 40.96

↪ Area of equilateral Δ = 1.73 × 10.24

↪ Area of equilateral Δ = 17.71152 m².

For information:

• Area of Δ = ¹/2 × base × height
• Area of square = (side)²
• Area of rectangle = Length × Base
• Area of rhombus = ¹/2 × d1 × d2
• Area of parallelogram = Base × Height
• Area of trapezium = ¹/2 × (a + b) × h

Answer 2

Answer:

$\huge \bf \: question$

find the area and height of and equilateral triangle whose each side measures 6.4m ( take √3 = 1.73 in each case)

$\huge \bf \: to \: find$

• Height of equilateral traingle
• Area of equilateral traingle

$\huge \bf \: answer$

Height of equilateral triangle = √3/2 × side

Height of equilateral triangle = √3/2 × 6.4 m

Height of equilateral triangle = √3 × 3.2

Height of equilateral traingle = 5.536 m

$\huge \fbox {height \: =5.536 m}$

area of equilateral traingle = √3/4 × side²

area of equilateral traingle = √3/4 × (6.4²)

area of equilateral traingle = √3/4 × 40.96

area of equilateral traingle = 1.73 × 10.24

$\huge \fbox {area \: =7.71152}$