Find the area and length of AD.
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From the question it is given that,
AB = 5 cm, BC = 13 cm, AC = 12 cm
We know that,
Area of the ΔABC = ½ × base × height
= ½ × AB × AC
= ½ × 5 × 12
= 1 × 5 × 6
= 30 cm2
Now,
Area of ΔABC = ½ × base × height
30 = ½ × AD × BC
30 = ½ × AD × 13
(30 × 2)/13 = AD
AD = 60/13
AD = 4.6 cm
Therefore area of triangle ABC = 30cm^2 and length of AD = 4.6cm
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