Question

Find the area and perimeter of a rectangle whose length and breadth are in the ratio 63:16 and diagonal is equal to 130 cm

Answer 1

area of rectangle A=LXB
ratio of length and breadth L:B=63:16
length L=63 and B=16
A =16x 63
A=1008sq.cm
perimeter p=2(L+B)
p=2x16x63
p=2016 cm

Answer 2

let length =63x
bredth =16 x
length,breadth and diagonal makes a triangle.the angle between lenglth and bredth is 90 degree
length ^2+ bredth ^2= diagonal ^2
63x^2+ 16x^2=130^2
3969x^2+256x^2=130^2
√4225x^2=130
65x=130
x=130/65=2
length =63*2=126
bredth =16*2=32
perimeter = 2*(126+32)
=2*158
=316cm
area =126*32=4032cm