Math, asked by mathewnevin555, 1 month ago

Find the area and perimeter of a rectangle whose length and breadth are in ratio 63:16 and diognal is equal to 130cm

Answers

Answered by hetalwagh25
0

Answer:

A=1008sq.cm

p=2016 cm

Step-by-step explanation:

area of rectangle A=LXB

ratio of length and breadth L:B=63:16

length L=63 and B=16

A =16x 63

A=1008sq.cm

perimeter p=2(L+B)

p=2x16x63

p=2016 cm

Answered by az25875
0

Answer:Ok

Step-by-step explanation:

Area of a rectangle- A=LXB

ratio of length and breadth- L:B=63:16

length- L=63 and B=16

A=16x 63

A=1008sq.cm

perimeter p= 2(L+B)

p=2×16×63

p=2015 cm

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