Question

find the area and perimeter of a rectangle whose length and breadth are in the ratio 63:16 and diagonal is equal to 130 cm.





i want answer steps bye step

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Answer 1

Answer:

diagonal of rectangle is

$\sqrt{l { }^{2} + b {}^{2} }$

$\sqrt{65 {}^{2} + 16 { }^{2} } = 65$

2×65 = 130

so,

length = 2×63 = 126

breadth = 2 ×16 =32

perimeter is 2(length × breadth)

=> 2(126+32) = 316

Area is (length × breadth)

=> 126×32 = 4032