Question

find the area and perimeter of a rectangle whose length is equal to 7 metre and breadth is equal to 8 metre​

Answer 1

Answer:

We know that

in the case of a rectangle having length = l

and

breadth = b

Perimeter of that rectangle is given by

$perimeter \: = \: 2(l + b)$

And

Area of that rectangle is given by

$area \: = \: l \times b$

Here in this question,

l = 7m

and

b=8m

So

$perimeter = 2( 7 + 8) \\ = 2 \times 15 \\ = 30 {m}$

And

$area = 7 \times 8 \\ = 56 {m}^{2}$

Answer 2

Answer:

Perimeter of the rectangle = 2 ( l + b )

P = 2 ( 7 + 8 )m

P = 2*15

P = 30 m

Area of the rectangle = l*b

A = 7*8

A = 56 m²

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