Find the area and perimeter of a right angled triangle with base 8 cm and hypotenuse 17 cm
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Given:
base = 8cm
hypotenuse = 17cm
We know that the area of a triangle is 1/2 x bh. But we only have base here. So let's find the height/altitude of this triangle using the Pythagoras Theorem.
Pythagoras Theorem : hypo² = base² + height²
We want to find the height here. So, let's make some tweaks to this equation.
height² = hypo² - base²
= h² = 17² - 8²
= h² = 289-64 = 225
∵ h = √225
h = 15cm
So now, we have all the measures we need for finding the area and perimeter of this triangle. Let's continue with our solving!
Area = 1/2 x bh
= 1/2 x 8 x 15
= 1/2 x 120
= 60
Area = 60cm²
Perimeter of a triangle = a + b + c
(basically means add all 3 sides.)
= base + hypo + height
= 8 + 15 + 17
= 40cm
Heya! Hope it was helpful. Pls mark brainliest if it helped.
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