Question

Find the area and perimeter of a sector with central angle of 60degree in a circle of radius 7cm

Answer 1

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θ = 60°
r = 7cm

$area \: of \: sector = \frac{θ}{360} \pi{r}^{2}$

$\frac{60}{360} \times \frac{22}{7} \times 7 \times 7$

$\frac{1}{6} \times 22 \times 7$

$= \frac{77}{3}$

$25.6cm {}^{2}$

Perimeter of sector = 2r + (r×θ)

= 2×7 + (7×60)
14+420
= 434cm^2.

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Answer 2

θ = 60°

r = 7cm

area \: of \: sector = \frac{θ}{360} \pi{r}^{2}areaofsector=

360

θ

πr

2

\frac{60}{360} \times \frac{22}{7} \times 7 \times 7

360

60

×

7

22

×7×7

\frac{1}{6} \times 22 \times 7

6

1

×22×7

= \frac{77}{3}=

3

77

25.6cm {}^{2}25.6cm

2

Perimeter of sector = 2r + (r×θ)

= 2×7 + (7×60)

14+420

= 434cm^2.