Question

find the area and perimeter of a sector with Central angle of 60° in a circle of radius 7 cm



Please
I need it fast....​

Answer 1

θ = 60°

r = 7cm

area \: of \: sector = \frac{θ}{360} \pi{r}^{2}areaofsector=

360

θ

πr

2

\frac{60}{360} \times \frac{22}{7} \times 7 \times 7

360

60

×

7

22

×7×7

\frac{1}{6} \times 22 \times 7

6

1

×22×7

= \frac{77}{3}=

3

77

25.6cm {}^{2}25.6cm

2

Perimeter of sector = 2r + (r×θ)

= 2×7 + (7×60)

14+420

= 434cm^2.

Answer 2

hope this answer help you