find the area and perimeter of a sector with Central angle of 60° in a circle of radius 7 cm
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Answered by
6
θ = 60°
r = 7cm
area \: of \: sector = \frac{θ}{360} \pi{r}^{2}areaofsector=
360
θ
πr
2
\frac{60}{360} \times \frac{22}{7} \times 7 \times 7
360
60
×
7
22
×7×7
\frac{1}{6} \times 22 \times 7
6
1
×22×7
= \frac{77}{3}=
3
77
25.6cm {}^{2}25.6cm
2
Perimeter of sector = 2r + (r×θ)
= 2×7 + (7×60)
14+420
= 434cm^2.
Answered by
6
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