Question

Find the area and perimeter of a square of side 13.5 CM

Answer 1

AnsweR :

• ➫ Area of square is 182.25 cm.sq.
• ➫ Perimeter of square is 54 cm.

ExplanatioN :

Given,

Side of square= 13.5

Area of square=(side)^2

=(13.5)^2

=13.5×13.5

=182.25 cm.sq.

Area of square is 182.25 cm.sq.

Given,

Side of square= 13.5

Perimeter of square = (4*side)

= 13.5×4

= 54 cm.

Perimeter of square is 54 cm.

Answer 2

Answer:

${\large{\underline{\underline{\bf{Given \: : - }}}}}$

• ⟶ Side of square = 13.5 cm

$\begin{gathered}\end{gathered}$

${\large{\underline{\underline{\bf{To \: Find\: : - }}}}}$

• ⟶ Area of square
• ⟶ Perimeter of square

$\begin{gathered}\end{gathered}$

${\large{\underline{\underline{\bf{Using \: Formulae\: : - }}}}}$

• ⟶ Perimeter of square = 4 × side

$\begin{gathered}\end{gathered}$

${\large{\underline{\underline{\bf{Diagram\: : - }}}}}$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf}\put(-0.5,4.2){\bf}\put(4.2,-0.5){\bf}\put(4.2,4.2){\bf}\put(1.5,-0.6){\bf\large 13.5\ cm}\put(4.4,2){\bf\large 13.5\ cm}\end{picture}$

$\begin{gathered}\end{gathered}$

${\large{\underline{\underline{\bf{Solution\: : - }}}}}$

$\green\bigstar$ Finding the area of square

$\dashrightarrow{\sf{Area_{(square)} = {(side)}^{2}}}$

• Substuting the values

$\dashrightarrow{\sf{Area_{(square)} = {(13.5)}^{2}}}$

$\dashrightarrow{\sf{Area_{(square)} = 13.5 \times 13.5}}$

$\dashrightarrow{\sf{Area_{(square)} = \dfrac{135}{10} \times \dfrac{135}{10} }}$

$\dashrightarrow{\sf{Area_{(square)} = \dfrac{135 \times 135}{10 \times 10}}}$

$\dashrightarrow{\sf{Area_{(square)} = \dfrac{18225}{10 0}}}$

$\dashrightarrow{\sf{Area_{(square)} = \dfrac{18225}{100}}}$

$\dashrightarrow{\sf{Area_{(square)} = \cancel{\dfrac{18225}{100}}}}$

$\dashrightarrow{\sf{Area_{(square)} = \dfrac{3645}{20}}}$

$\dashrightarrow{\sf{Area_{(square)} = \cancel{\dfrac{3645}{20}}}}$

$\dashrightarrow{\sf{Area_{(square)} = 182.25 \: {cm}^{2} }}$

$\bigstar\red{\underline{\boxed{\bf{Area \: of \: square= 182.25 \: {cm}^{2}}}}}$

∴ The area of square is 182.25 cm².

$\begin{gathered}\end{gathered}$

$\green\bigstar$ Finding the perimeter of square

${\dashrightarrow{\sf{Perimeter_{(square)}= 4 \times side}}}$

• Substuting the values

${\dashrightarrow{\sf{Perimeter_{(square)}= 4 \times 13.5}}}$

${\dashrightarrow{\sf{Perimeter_{(square)}= 4 \times \dfrac{135}{10}}}}$

${\dashrightarrow{\sf{Perimeter_{(square)}= \cancel{4} \times \dfrac{135}{\cancel{10}}}}}$

${\dashrightarrow{\sf{Perimeter_{(square)}= 2\times \dfrac{135}{5}}}}$

${\dashrightarrow{\sf{Perimeter_{(square)}= 2\times \cancel{\dfrac{135}{5}}}}}$

${\dashrightarrow{\sf{Perimeter_{(square)}= 2\times 27}}}$

${\dashrightarrow{\sf{Perimeter_{(square)}= 54 \: {cm}^{2} }}}$

$\bigstar\red{\underline{\boxed{\bf{Perimeter \: of \: square= 54 \: {cm}^{2}}}}}$

∴ The perimeter of square is 54 cm.

$\begin{gathered}\end{gathered}$

${\large{\underline{\underline{\bf{Answer\: : - }}}}}$

• The area of square is 182.25 cm².
• The perimeter of square is 54 cm.

$\begin{gathered}\end{gathered}$

${\large{\underline{\underline{\bf{Learn \: More\: : - }}}}}$

$\green\bigstar$ Formulas of area

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$

$\begin{gathered}\end{gathered}$

${\large{\underline{\underline{\bf{Request\: : - }}}}}$

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