Question

Find the area and perimeter of a square whose each side measures 9 cm​

Answer 1

Step-by-step explanation:

SOLUTION

Given,

Side of the square measures 9cm.

Find,

The area and perimeter of a square.

SO,

We know that,

Area of square

$= (side)^{2}$

$= > (9) ^{2}$

$= > 9 \times 9$

$= > 81cm^{2}$

Than,

We know that,

Perimeter of square

$= 4 \times side$

$= > 4 \times 9$

$= > 36cm.$

Hence,

Area of square is 81cm².

Perimeter of square is 36cm.

Answer 2

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$\huge{\fbox{\blue{Given:-}}}$

Side of a square:- 9 cm.

⠀

$\huge{\fbox{\blue{To find:-}}}$

• Area of the square.
• Perimeter of the square.

⠀

$\huge{\fbox{\blue{Solution:-}}}$

Area of the square:-

$area \: of \: a\: square = {side}^{2} \\ \implies \: area \: of \: the \: given \: square = {9}^{2} \\ \implies \: area \: of \: the \: given \: square = 81 {cm}^{2}$

⠀

Perimeter of the square:-

$perimeter \: of \: a \: square = 4 \times side \\ \implies \: perimeter \: of \: the \: given \: square = 4 \times 9 \\ \: \: \implies \: perimeter \: of \: the \: given \: square =36 {cm}$

⠀

$\huge{\fbox{\blue{Formulae Used:-}}}$

$area \: of \: a \: square = {side}^{2} \\ perimeter \: of \: a \: square = 4 \times side$