find the area and perimeter of an isosceles right angled triangle each of equal sides measures 10 cm
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Area: (10×10 / 2) 50 cm2
Perimeter: (10×3) 30 cm
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side = 10cm
area of triangle=1/2×b×h
=1/2×10×10
=5×10
=50cm2
using Pythagoras theorem
H2=B2 + P2
H2=100+100
H2=200
H= √200cm
perimeter of triangle = sum of all sides
= √200+10+10
=20+√200cm
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