find the area and perimeter of an isosceles right angled triangle each of whose sides measures 10 cm
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By phythagoras theoram
h×h=b×b+p×p
h×h=100cm + 100cm
h2= 200cm
area of triangle
1/2 b ×h
1/2 × 200cm
100cm
area = 100 CM
perimeter of triangle
sum of all sides
200cm
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Answer:
Step-by-step explanation:
Area = 1/2 × 10 × 10
= 50 sq cm
Perimeter = sum of three sides
= 10 + 10 + √200
= 34.1 4 cm
(Hyp)^2 = 10^2 + 10^2
= 100 + 100
=200
Hyp. = √200
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