Question

Find the area and perimeter of an isosceles right angled triangle, each of whose equal sides measures 10 cm. Take root 2 = 1.414

Answer 1

2=(P)^2+(B)^2

=10^2+10^2

area of isosceles=1/2×base ×height

=1/2×10×10=5sq.cm

using Pythagoras

h^2=10^2+10^2

h^2=200

h=10×√2=10×1.414

=14.14cm

perimeter=sum of all sides

=10+10+14.14=34.14cm.