Question

find the area and perimeter of each of the following figures given.Friends plz solve it with correct and full explanation.​

Answer 1

lets mark it ABCD

Are of rectangle ABCD = l×b

= 70×56

= 4424

now we have semicircle with diameter Ad = 56

radius of semicircle =

$\frac{56}{2} = 28$

radius = 28

area of semicircle AD :

$\pi \frac{ {r}^{2} }{2} = \frac{22}{7} \times \frac{28 \times 28}{2} = 1232 \: square \: units$

similarly area of BC will be 1232 (same radius )

semicircle AB diameter = 70

$\frac{70}{2} = 35$

Radius = 35 cm

area of semicirle would be :

$\frac{22}{7} \times \frac{35 \times 35}{2} = 1925$

total area we had found

4424+1232+1232+1925+1925

=10738

thanks

mark brainliest

@ I could show you how to defeat the night