Question

find the area and perimeter of figure ABCD where angle b is equal to 90 degree and Angle d is equal to 90 degree ab is equal to 6 CM BC is equal to 8 metre and d is equal to 24​

Answer 1

Answer:

here is your answer friend

Answer 2

Answer

Area of △BCD=21×24×10=120m2

Use pythagoras theorem in ΔCBD

CD2+BC2=DB2

102+242=DB2

676=DB2

⟹DB=26m

Area of △ABD⇒ (By heron's) 

S=226+18+16=30

A=30(30−26)(30−18)(30−16)

=141.98≈142m2

∴ Total area =142+120=262m2