find the area and perimeter of quadrilateral A B C D in which Ab 15 cm bc 12 cm cd 13 da 14 angle A CB is 90 °
Answers
Answered by
1
Answer: 126.3
Step-by-step explanation: by puthagoras theorem AC = Root of AB square - BC square
So. AC = 9
So area of triangle ACB = 9* 12 * 1/2
= 54
By herons formula area of triangle ADC =
√ 18 * 4 * 5 * 9
= 72.3
Total area = 72.3 + 54 = 126.3
Similar questions