Question

➡Find the area and perimeter of rectangle , where length and Wight are given as 12 and 8 Cm .

Also, find length of diagonal . ​

Answer 1

$\large{\underline{\underline{\mathfrak{\green{\sf{Answer-}}}}}}$

★ Area of rectangle = 96 cm²

★ Perimeter of rectangle = 40 cm

★ Diagonal of rectangle = 4√13 cm

$\large{\underline{\underline{\mathfrak{\green{\sf{Figure-}}}}}}$

$\setlength{\unitlength}{2cm}\begin{picture}(16,4)\thicklines\put(8,3){\circle*{0.1}}\put(7.8,3){\large{D}}\put(7.2,2){\mathsf{\large{8cm}}}\put(8,1){\circle*{0.1}}\put(7.8,1){\large{A}}\put(9.3,0.8){\mathsf{\large{12cm}}}\put(11.1,1){\large{B}}\put(8,1){\line(1,0){3}}\put(11,1,){\circle*{0.1}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\put(11,3){\circle*{0.1}}\put(11.1,3){\large{C}}\end{picture}$

$\large{\underline{\underline{\mathfrak{\green{\sf{Formula\:used-}}}}}}$

$\sf{Area\:of\:rectangle=Length×Width}$

$\sf{Perimeter\:of\:rectangle=2(Length+Width)}$

$\sf{Diagonal\:of\:rectangle= \sqrt{ {length}^{2} + {width}^{2} } }$

$\large{\underline{\underline{\mathfrak{\green{\sf{Explanation-}}}}}}$

$\begin{lgathered}\bold{Given} \begin{cases}\sf{Length=12\:cm} \\ \sf{Width=8\:cm}\end{cases}\end{lgathered}$

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$\begin{lgathered}\bold{To\:find} \begin{cases}\sf{Area\:of\:rectangle} \\ \sf{Perimeter\:of\:rectangle}\\ \sf{Diagonal\:of\:rectangle}\end{cases}\end{lgathered}$

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Solution :

★ $\sf{Area\:of\:rectangle=Length×Width}$

$\implies$ $\sf{Area\:of\:rectangle=12×8}$

$\implies$ $\sf{Area\:of\:rectangle=96cm^2}$

★ $\red{\sf{Perimeter\:of\:rectangle=2(Length+Width)}}$

$\implies$ $\sf{Perimeter\:of\:rectangle=2(12+8)}$

$\implies$ $\sf{Perimeter\:of\:rectangle=2(20)}$

$\implies$ $\red{\sf{Perimeter\:of\:rectangle=40cm}}$

★ $\sf{Diagonal\:of\:rectangle= \sqrt{ {length}^{2} + {width}^{2} } }$

$\implies$ $\sf{Diagonal\:of\:rectangle= \sqrt{ {12}^{2} + {8}^{2} } }$

$\implies$ $\sf{Diagonal\:of\:rectangle= \sqrt{144+64} }$

$\implies$ $\sf{Diagonal\:of\:rectangle=\sqrt208}$

$\implies$ $\red{\sf{Diagonal\:of\:rectangle=4\sqrt13cm}}$

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Answer 2

Answer:

area of rectangle= l×w

A=12×8

A=96

perimeter of the rectangle=2(l+w)

=2(12+8)

=2(20)

=40

length of the diagonal=√w²+l²

=√8²+12²

= 14.42

Step-by-step explanation:

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