find the area and perimeter of the following rectangle whose dimensional are length 5 M breadth 32m
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4
Area = l×b
5×32 = 160 m2
Perimeter = 2(l+b)
2(5+32)
2(37)
74m
5×32 = 160 m2
Perimeter = 2(l+b)
2(5+32)
2(37)
74m
mohit16016:
right
Answered by
1
area of a rectangle = l*b = 32*5= 160m2
perimeter of a rectangle = 2(l+b) = 2(32+5) = 74m
perimeter of a rectangle = 2(l+b) = 2(32+5) = 74m
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