Question

find the area and perimeter of the rectangle?

Answer 1

hey User !!!

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here's your correct ....


SOLUTION

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We know,
area of rectangle = length× breadth

$= \sqrt{8} \times \sqrt{2} \\ = \sqrt{8 \times 2 } \\ = \sqrt{16} \\ = 4$
so the area of rectangle is
$4cm ^{2}$
Now ,

The perimeter of rectangle = 2 (l + b)
$= 2( \sqrt{8} + \sqrt{2} ) \\ = 8.485cm$
so, the perimeter of rectangle is 8.485cm

I hope
this helps
you

Answer 2

$\huge{\underline{\underline{\purple{\mathfrak{Answer :}}}}}$

♠ Given :

(L) Length of rectangle is √8 cm

(B) Breadth of rectangle is √2 cm

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♠ To Find :

Perimeter and Area of rectangle

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♠ Solution :

$\setlength{\unitlength}{2cm}\begin{picture}(16,4)\thicklines\put(8,3){\circle*{0.1}}\put(7.8,3){\large{D}}\put(7.2,2){\mathsf{\large{Root2cm}}}\put(8,1){\circle*{0.1}}\put(7.8,1){\large{A}}\put(9.3,0.8){\mathsf{\large{Root8cm}}}\put(11.1,1){\large{B}}\put(8,1){\line(1,0){3}}\put(11,1,){\circle*{0.1}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\put(11,3){\circle*{0.1}}\put(11.1,3){\large{C}}\end{picture}$

We know that,

$\Large{\boxed{\boxed{\blue{\sf{Perimeter = 2(L + B)}}}}}$

Perimeter = 2(√8 + √2)

Perimeter = 2(2√2 + √2)

Perimeter = 2(3√2)

Perimeter = 6√2 cm

$\large{\boxed{\green{\sf{Perimeter = 6 \sqrt{2} \: cm }}}}$

$\rule{200}{2}$

Now,

$\Large{\boxed{\boxed{\pink{\sf{Area = L \times Breadth}}}}}$

Area = √8 * √2

Area = √16

Area = (√4)²

Area = 4 cm²

$\large{\boxed{\orange{\sf{Area = 4 \: cm^2}}}}$

$\rule{200}{2}$

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