Question

Find the area and perimeter of the rectangle whose length is 15 cm and the length of one diagonal is 17 cm

Answer 1

length= 15 cm let breadth be x metre
diagonal = 17 cm

so by applying PGT
l^2+b^2=d^2
225+x^2=289
x^2= 289-225
x^2=64
x=8cm
area = l× b
=15×8
=120 cm^2

perimeter = 2 (l+b)
=2 (15+8)
=2×23
46cm

Answer 2

Answer:

Area = $120m^2$ and Perimeter = $46$ cm

Step-by-step explanation:

As per the given data, we have to find the area and perimeter of rectangle.

Given that:-

Length = $15$ cm  (Length = L;B = Breadth;H = diagonal)

Height = $17$ cm  

Now,

$=>L^2+B^2=H^2$

$=>(15)^2+B^2=(17)^2$

By simplifying it further, we get

$=>225+B^2=289$

$=>B^2=289-225$

$=>B^2=64$

By taking square root on both sides,

$=>B=8$ cm

So, breadth is $8$ cm.

We know that,

Area of rectangle = length $\times$ breadth

=> 15 $\times$ $8$

$=> 120m^2$

Perimeter of reactangle = 2 [ L $+$ B ]

=> $2 [ 15 + 8 ]$

=> $2 [ 23 ]$

=> $46$ cm

Hence, the value of area is $120m^2$ and Perimeter is $46$ cm