Question

find the area and permeter of a room whose dimension are 8.5 and 11.25m

Answer 1

so we know that the shape of the room is rectangle
area would be
l*b
let's take l as 11.25
and b as 8.5
if we multiply them we get,
95.625 the area is
95.625sq.m
perimeter is
2(l+b)
2(11.25+8.5)
2(19.75)
which is
39.5m
this is the perimeter
if this helped u then mark as brainliest

Answer 2

Hlo friend... Cutiepie Here...

Nice question..

Here is ur answer :

Length l of room = 8.5 m

Breadth b of room = 11.25 m

Area of room = Length × breadth

$= l \times b$

$= 8.5 \times 11.25$

$= 95. 625$


Perimeter of room= 2 ( length + breadth )

$= 2( l+ b)$

$= 2(8.5 + 11.25)$

$= 2 \times 19.75$

$= 39.5$



Area of room = 95.625m²

Perimeter of room = 39.5m²


HOPE IT HELPS YOU..

REGARDS
@sunita