Find the area and the perimeter of a square whose diaggonal is 10 from Pythagoras theorem
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Answered by
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Answer:
Area = 50
Perimeter = 20✓2
( I did not use units as none were given in the question)
Step-by-step explanation:
Diagonal is 10.
Let side of square be s.
By Pythagoras theorem,
10² = s² + s²
100 = 2s²
s = ✓50= 5✓2
Therefore area = (side)² = s² = 50
Perimeter = 4 x 5✓2
=20✓2
Hope that it helps you.
Answered by
0
Answer:area=50
Perimeter=20√2
Step-by-step explanation:
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