find the area and the perimeter of the rectangle whose length of the 1 diagonal is 17 cm
Answers
Answered by
1
From the figure the Triangle is a right angle triangle
So, l² + b² =d²
b=√(17² - 1²)=√288 =12√2 cm
So perimeter of a Rec =2(l+b)=2(17 + 12√2 )=34 + 24√2 cm
Also Area of rectangle =l*b=17*12√2=204√2 cm²
So, l² + b² =d²
b=√(17² - 1²)=√288 =12√2 cm
So perimeter of a Rec =2(l+b)=2(17 + 12√2 )=34 + 24√2 cm
Also Area of rectangle =l*b=17*12√2=204√2 cm²
Attachments:
Similar questions