find the area and the perimeter of the shaded region here ABCD is a square of side 21 cm and it is a semicircle
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Answer:
area of shaded region = area of square-area of semicircle
area= 21×21-22/7×21/2×21/2×1/2
=441-1617/4=1764-1627/4=137/4
perimeter= sum of three sides of square+ perimeter of semicircle
perimeter= 21+21+21+2(22/7)21/2
=21+21+21+154=217
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6
Answer:
Given,
ABCD is a square
side=21cm=AB=BC=CD=AD
AED is a semicircle
Area of square ABCD=side×side=(21×21)cm^2=441cm2
Area of semicircle AED=πr^2/2=22/7×21/2×21/2=173.25cm^2
Area of shaded region=area of square ABCD-area of semicircle AED=441-173.25=267.75cm^2
Now,
Perimeter of Square ABCD=4×side=4×21=84cm
Perimeter of semicircle AED =(π+2)r=(22/7+2)21/2=54cm
Perimeter of shaded region=perimeter of square ABCD - Perimeter of semicircle AED
= 84-54=30cm
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