Find the area angled triangle whose one leg to 5cm and hypotenuse is 13cm
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Given :-
- Hypothenuse (H) = 13cm
- Perpendicular (P) = 5cm
To Find :-
- Area of Triangle
Solution :-
Using Pythagoras theorem :
⟾ (H)² = (P)² + (B)²
⟾ (13)² = (5)² + (Base)²
⟾ 169 = 25 + (Base)²
⟾ 169 - 25 = (Base)²
⟾ 144 = (Base)²
⟾ √144 = Base
⟾ 12cm = Base
Now,
Applying Area of Triangle :
➞ Area of Triangle = ½ × Base × Height
➞ Area of Triangle = ½ × 12 × 5
➞ Area of Triangle = 6 × 5
➞ Area of Triangle = 30cm²
Thus Area of Triangle is 30cm²
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