Question

Find the area area of the quardilateral in which the length of one diagonals is 20m and perpendiculars drawn to it from the opposite vertices are 11m and 9m.

Answer 1

Answer:

200$m^{2}$

Step-by-step explanation:

We know that quadrilateral is composed of two triangles

Length of the diagonal = 20 m

Length of 1st perp. = 11 m

Area of 1st triangle = (1/2 * 20 * 11)$m^{2}$ = 110$m^{2}$

Length of 2nd perp. = 9 m

Area of 2nd triangle = (1/2 * 20 * 9 )$m^{2}$ = 90$m^{2}$

Area of the quadrilateral = Sum of area of both the triangles

                                        = ( 110 + 90) $m^{2}$

                                        = 200$m^{2}$

Answer 2

Answer

200 meter square

explanation

upper side