Find the area between the curves y=2/x and y=−x+3.
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Answer:
A=∫ba|=∫π0|sinx−cosx|dx=∫π/40(cosx−sinx)dx+∫ππ/4(sin=[sinx+cosx]|π/40+[−cos=(√2−1)+(1+ The area of the region is 2√2 units2. If R is the region between the graphs of the functions f(x)=sinx and g(x)=cosx over the interval [π/2,2π], find the area of region R.
Step-by-step explanation:
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Step-by-step explanation:
The area enclosed between y
2
=x and y=x
October 15, 2019
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Hashmat Shaikh
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VIDEO EXPLANATION
ANSWER
Intersection point of two curves are O(0,0) and A(1,1)
∴ Required area =∫
0
4
(y
2
−y
1
)dx
∫
0
1
(
x
−x)dx
=[
3/2
x
3/2
−
2
x
2
]
0
1
=
3
2
[1−0]−
2
1
(1−0)
=
3
2
−
2
1
=
6
1
unit
solution
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