Find the area bounded by the curve y = 10 – 3x – x
and the x-axis.
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Given the curve, xy−3x−2y−10=0⇒xy−2y=3x+10⇒y(x−2)=3x+10⇒y=x−23x+10
∴ Area bounded by the curve xy−3x−2y−10=0, x-axis and the lines x=3,x=4,
∫34∣y∣dx=∫34(x−23x+10)dx=∫34(x−23x−6+16)dx=∫34(3+x−216)dx=[3x+16log∣x−2∣]34=[12+16log∣2∣−9−16log∣1∣]=16log2+3squareunits.
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