find the area bounded by the curve y=3x^2+2x+2 the x-axis and the ordinates x=0 and x=1
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Answer:
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Answered by
1
Answer:
y=3x+2,x=−1,x=1
Required area=
∣
∣
∣
∣
∫
−1
3
−2
(3x+2)dx
∣
∣
∣
∣
+∫
−
3
2
1
(3x+2)dx
=
∣
∣
∣
∣
∣
∣
∣
[
2
3x
2
+2x]
−1
−
3
2
∣
∣
∣
∣
∣
∣
∣
+[
2
3x
2
+2x]
−
3
2
1
=
∣
∣
∣
∣
∣
∣
3
2
−
8
4
−(
2
3
−2)
∣
∣
∣
∣
∣
∣
+
2
3
+2−(
3
2
−
3
4
)
=
∣
∣
∣
∣
∣
∣
−
3
2
+
2
1
∣
∣
∣
∣
∣
∣
+
2
7
+
3
2
=
∣
∣
∣
∣
∣
∣
−
6
1
∣
∣
∣
∣
∣
∣
+
6
25
=
6
1
+
6
25
=
3
13
squnit
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