Question

find the area bounded by the curve y=cos x between x=0 and x=3pie/2

Answer 1

Answer:

The desired are =∫0π/4(cosx)dx

+∫π/45π/4(sinx−cosx)dx+∫5π/43π/2(cosx−sinx)dx

=2[sinx+cosx]0π/4+[−cosx−sinx]π/45π/4

(As the first and third integrals are equal in magnitude )

=2(21+21−1)+(21+21+21+21)

28−2=42−2