Question

find the area bounded by the curve Y =sin x between X = zero and X =2 π​

Answer 1

Solution :

area=2 area of1st1st part

=2∫π0f(x)dx2∫0πf(x)dx

=2∫π0sinxdx2∫0πsinxdx

=2(−cosx)π02(-cosx)0π

=2(−cosπ+cos0)2(-cosπ+cos0)

=2(1+1)2(1+1)

=4unit2