find the area bounded by y=x and y=x²
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1
Answer:
First we find the cordinates of point P
y=x and y=x2
⟹x=x2
⟹x=0,1
The value x=0 correspond to O(0,0).
For P, x=1
Now, the required area
A=∫01(y1−y2)dx
=∫01(x−x2)dx
=[2x2−3x3]01
⟹A=1/6
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