Question

Find the area contained by the curve y =3x2
from x = 1 to x = 3.​

Answer 1

Answer:

Find the area bounded by the curve y=3x+2, x-axis and ordinate x=-1andx=1. 162.0 K LIKES. 197.4 K VIEWS. 197.4 K SHARES.

Answer 2

Answer:

Area of the parabolic equation $y=3x^{2}$ from x = 1 to x = 2 is 26 units square.

Step-by-step explanation:

Given the equation of curve is $y=3x^{2}$ and the limit is from x = 1 to x = 3.

$y=3x^{2}$ is the equation of an upward parabola.

The area of parabola equation will be found by integrating the equation from x = 1 to x= 3.

Therefore,

$Area \ of \ parabolic \ curve =\int\limits^a_b {y} \, dx$

Substituting the value of y and given limits,

$Area \ of \ parabolic \ curve =\int\limits^3_1 {3x^{2} } \, dx\\Area \ of \ parabolic \ curve=[\frac{3x^{3} }{3} ]^3_1\\Area \ of \ parabolic \ curve=[x^{3} ]^3_1\\Area \ of \ parabolic \ curve=(27-1)\\Area \ of \ parabolic \ curve=26 \ unit \ square$

Therefore, the area contained by the curve $y=3x^{2}$ from x = 1 to x = 3 is 26 units square.