Question

find the area enclosed

Answer 1

Area of inner square=s²
→(20)²
→400m²

Area of left side triangle = 1/2×b×h

$\frac{1}{2 } \times 20 \times 10 \\ 1 \times 10 \times 10 \\ 100m {}^{2}$
Area of right side triangle = √3/4×s²
→√3/4×20×20
→1.73×20×20
→692m²



Thank you!!!

Hope this will helpful for you.

Please mark me as brainliest because I will get new rank because of you.