find the area enclosed by curve xy^2=4(2-x) and y axis and also the value of the solid formed by the revolution of the curve through four right angles about the x axis
Answers
Answered by
0
Answer:
The given curve is symmetrical about x-axis and meet it at (a,0).
The line x=0 is asymptote.
Required area =2∫
0
a
ydx
=2]∫
0
a
a
x
a−x
dx
Put x=asin
2
θ
⇒dx=2asinθcosθdθ
Therefore, area =2∫
0
π/2
a
sinθ
cosθ
×2asinθcosθdθ
=2a
2
∫
0
π/2
2cos
2
θdθ=2a
2
∫
0
π/2
(1+cos2θ)dθ
=2a
2
[θ−
2
sinθ
]
0
π/2
=2a
2
(
2
π
)=πa
2
HERE IS UR ANSWER
MARK ME AS BRAINLIEST
Attachments:
Similar questions